JAVA如何将函数作为方法参数传入

JAVA如何将函数作为方法参数传入

1、创建函数接口类

//函数接口类 public interface IFunction { Map<String, Object> queryYearData(Map<String, Object> map); };

2、方法调用时，使用lambda表达式传入函数参数

public CommonResult<List<Map<String, Object>>> queryGeneralFollowUpYear(String loginType) { return queryYearData(loginType, (map) -> mapper.queryGeneralFollowUpYear(map)); }

3、具体方法实现

private CommonResult<List<Map<String, Object>>> queryYearData(String loginType, IFunction myFunction) { SysUser sysUser = SystemUtil.getLoginUser(loginType); if (null == sysUser){ return new CommonResult<>(CommonResultEmnu.INVALID_USER); } Map<String, Object> map = new HashMap<>(); Long createSysId = sysUser.getId(); map.put("createId", createSysId); Map<String, Object> recordYear = myFunction.queryYearData(map); return new CommonResult<>(ChartUtil.getLastTwelfthMonthData(recordYear)); }

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新时代农民工